3cos^2x+sin^2x+5sinx=0

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Solution for 3cos^2x+sin^2x+5sinx=0 equation:


Simplifying
3cos2x + sin2x + 5sinx = 0

Reorder the terms:
3cos2x + 5insx + in2sx = 0

Solving
3cos2x + 5insx + in2sx = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-5insx' to each side of the equation.
3cos2x + 5insx + -5insx + in2sx = 0 + -5insx

Combine like terms: 5insx + -5insx = 0
3cos2x + 0 + in2sx = 0 + -5insx
3cos2x + in2sx = 0 + -5insx
Remove the zero:
3cos2x + in2sx = -5insx

Add '-1in2sx' to each side of the equation.
3cos2x + in2sx + -1in2sx = -5insx + -1in2sx

Combine like terms: in2sx + -1in2sx = 0
3cos2x + 0 = -5insx + -1in2sx
3cos2x = -5insx + -1in2sx

Divide each side by '3os2x'.
c = -1.666666667ino-1s-1 + -0.3333333333in2o-1s-1

Simplifying
c = -1.666666667ino-1s-1 + -0.3333333333in2o-1s-1

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